Tuesday 18 June 2019

Solution of one system of boolean equations via reverse pass per Helen Mironchick

"Ignorance of the mapping method is still half the misfortune ..."
  B.D.

Down here we rely on technique proposed in 
https://mapping-metod.blogspot.com/2019/03/blog-post.html
Original system

((x1^x2=>x3)^x4=>x5)^x6=>x7=1
((y1^y2=>y3)^y4=>y5)^y6=>y7=1
x1=>y7=1


#1 - x1
#2 - x1^x2
#3 - (x1^x2=>x3)
#4 - (x1^x2=>x3)^x4
#5 - (x1^x2=>x3)^x4=>x5)
#6 - (x1^x2=>x3)^x4=>x5)^x6
#7 - ((x1^x2=>x3)^x4=>x5)^x6=>x7=1


   Passing Polyakov's Control



Another system solved via pass to center per Helen Mironchick unpublished manuscript 

((x1^x2=>x3)^x4=>x5)^x6=>x7=1
((y1^y2=>y3)^y4=>y5)^y6=>y7=1
x1=>y5=1


#1 - x1
#2 - x1^x2
#3 - (x1^x2=>x3)
#4 - (x1^x2=>x3)^x4
#5 - (x1^x2=>x3)^x4=>x5)
#6 - (x1^x2=>x3)^x4=>x5)^x6
#7 - ((x1^x2=>x3)^x4=>x5)^x6=>x7=1


    Passing Polyakov's Control




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