Saturday 14 September 2019

Solution of one 23rd problem in 08/2016 format kind of Practice test №1 as of 02.09.2019

Original system

(x1=>x2)^((z1⊕y1) =>x1)=1
(x2=>x3)^((z2⊕y2) =>x2)=1
(x3=>x4)^((z3⊕z3) =>x3)=1
(x4=>x5)^((z4⊕y4) =>x4)=1
(x5=>y5)=>z5 =1



   Needless to say that original task 23 from mentioned Practice test  №1 as of 02.09.2019
    "190902_Informatika_-_Probny_Variant_1_S_Resheniem.pdf" may be solved via 08/2016 format in a couple of minutes

        

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