Thursday 15 August 2019

Solution of one 23rd problems pending stream from Informatic BU in 08/2016 format

Original source


(x1=>x2)^((x1≡x2)=>(x3≡x4))=1
(x3=>x4)^((x3≡x4)=>(x5≡x6))=1
(x5=>x6)^((x5≡x6)=>(x7≡x8))=1
(x7=>x8)^((x7≡x8)=>(x9≡x10))=1

As soon as we have a conditions that allow us to determine the bits of x(j) for the arrows outgoing from the node of the 08/2016 chart, we can start. In particular case, we are ready to go ahead with  08/2016  diagram style.
Fork two 08/2016 diagram. The first one in details , the second one in brief.





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